select shortcut_name,
case s.object_type
when 21 then 'Mapping'
when 23 then (select o.object_type_name
from opb_object_type o
,opb_widget w
where w.widget_id = s.object_id
and w.widget_type = o.object_type
)
when 24 then 'Target'
when 25 then 'Source'
when 44 then 'Mapplet'
else 'Nothing'
end Object_Type,
decode(s.object_type, 21, (select f.subj_name
from opb_subject f,
opb_mapping m
where m.mapping_id = s.object_id
and m.subject_id = f.subj_id
),
23, (select f.subj_name
from opb_subject f,
opb_widget w
where w.widget_id = s.object_id
and w.subject_id = f.subj_id
),
25, (select f.subj_name
from opb_subject f,
opb_src src
where src.src_id = s.object_id
and src.subj_id = f.subj_id
),
24, (select f.subj_name
from opb_subject f,
opb_targ t
where t.target_id = s.object_id
and t.subj_id = f.subj_id
),
44, (select f.subj_name
from opb_subject f,
opb_widget w
where w.widget_id = s.object_id
and w.subject_id = f.subj_id
)
) obj_original_folder
from opb_shortcut s,
opb_subject f
where s.subject_id = f.subj_id
and f.subj_name = 'FOLDER_NAME'
Tuesday, June 15, 2010
Shortcut Object and its parent folder
Have you always wondered how to get the shortcut object & it's parent folder. This requirement is imminent in folders where you have tens of shortcut transformations & mappings. Below query can get you what you want.
Labels:
Informatica,
OPB Tables,
Parent folder,
PowerCenter,
Repository tables,
Shortcuts
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10 comments:
hi,
can u send me the architecture of informatica..
Thank u..
Ambika
Hi Ambika,
Can you tell me what you mean by Informatica architecture? You mean metadata architecture?
If you want 8.x architecture, can you send me your email address?
Cheers
Sarma
hi Radhakrishna,
I am new to Informatica and your blogs is very usefull to understand from high level to low level.
I would like to understand the metadata architecure, could you send an email to raju.10.thota@gmail.com please.
Thanks for help.
Hi RadhaKrishna,
I have gone through your performnace issue blogs. I satisfied very much with your explanation. I need PPT about informatica performance.
Could you please provide me.
Thanks,
Lavanya G
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Great post! I've got an idea here. Thanks for sharing this information. It will really help.
Hi Sharma,
Can you please help me out how to implement this portion in informatica.
i have a customer. Customer ID is primary key. For few customers, we are having 4 to 5 records. I need to give them rank in such a way that latest record of him should be one. We need to give rank to that customer by sorting. and the next customer may have one or two records and basing on the same we need to give the ranks again. How can implement this. For multiple records of the customers, we need are having start date, end date. WE need to group those records into one set and then have to give ranks. By rank trans, i tried but it was not giving correct results.
Thanks.
Thanks for the post sharma it help us a lot...
What’s up, I wish for to subscribe for this website to get latest updates, therefore where can I do it please help out.
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